JEE Main202118 Mar 2021Evening ShiftChemistryIonic EquilibriumActual
10 . 0   ml of Na 2 CO 3 solution is titrated against 0 . 2   M   HCl solution. The following values were obtained in 5 readings. 4 . 8   ml , 4 . 9   ml , 5 . 0   ml , 5 . 0   ml and 5 . 0   ml Based on these readings, and convention of titrimetric estimation of concentration of Na 2 CO 3 solution is ___ mM . (Round off to the Nearest integer)
Correct answer
0
Step-by-step solution
Most precise volume of HCl = 5   ml at equivalence point Meq. of Na 2 CO 3 = meq. of HCl Let molarity of Na 2 CO 3 solution = M , then M × 10 × 2 = 0 . 2 × 5 × 1 M = 0 . 05   mol / L = 0 . 05 × 1000 = 50   mM