JEE Main202117 Mar 2021Morning ShiftChemistryIonic EquilibriumActual
0 . 01 moles of a weak acid HA   K a = 2 . 0 × 10 - 6 is dissolved in 1 . 0   L of 0 . 1 M   HCl solution. The degree of dissociation of HA is __________ × 10 - 5 (Round off to the Nearest Integer). [Neglect volume change on adding HA and assume degree of dissociation < < 1 ]
Correct answer
0
Step-by-step solution
HA                 ⇌                         H +                               +       A - Initial conc.                    0 . 1 M 0 M                      Equ. conc.  ( 0 . 01 - x )         &#