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JEE Main20206 Sep 2020Evening ShiftChemistryIonic EquilibriumActual

If the solubility product of AB 2 is 3 . 20 × 10 - 11 M 3 , then the solubility of AB 2 in pure water is _______ × 10 - 4 mol L - 1 [Assuming that neither kind of ion reacts with water]

Correct answer

0

Step-by-step solution

AB 2 ⇌ A 2 + + 2 B − s 2 s K sp = 4 s 3 = 3 .20 × 10 − 11 So solubility = 2 × 10 − 4   mol   L − 1

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