JEE Main20206 Sep 2020Morning ShiftChemistryIonic EquilibriumActual
Arrange the following solutions in the decreasing order of pOH : (A) 0 . 01 MHCl (B) 0 . 01 MNaOH (C) 0 . 01 MCH 3 COONa (D) 0 . 01 MNaCl
Options
- A( A ) > ( C ) > ( D ) > ( B )
- B( A ) > ( D ) > ( C ) > ( B )
- C( B ) > ( C ) > ( D ) > ( A )
- D( B ) > ( D ) > ( C ) > ( A )
Correct answer
B. ( A ) > ( D ) > ( C ) > ( B )
Step-by-step solution
   pH 0 . 01 MHCl = 2 pH of 0 . 01 MNaOH = 12 pH of 0 . 01 MCH 3 COONa > 7 pH of 0 . 01 MNaCl = 7 So the order of pH : B > C > D > A So the order of pOH :     B < C < D < A