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JEE Main20207 Jan 2020Morning ShiftChemistryIonic EquilibriumActual

Two solutions, A and B , each of 100 L was made by dissolving 4 g of N a O H and 9.8 g of H 2 S O 4 in water, respectively. The p H of the resultant solution obtained from mixing 40 L of solution A and 10 L of solution B is ____________. ( log 2 = 0 . 3 )

Correct answer

0

Step-by-step solution

M H 2 S O 4 ⇒ 9.8 98 × 100 = 10 - 3 M N a O H ⇒ 4 40 × 100 = 10 - 3 = 40 × 10 - 3 - 10 × 10 - 3 × 2 50 = 20 50 × 10 - 3 O H - = 2 5 × 10 - 3 = 4 × 10 - 4 pOH = 4 - log 4 = 3 . 4 pH = 14 - 3 . 4 = 10 . 6

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