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JEE Main 201411 AprilOnline
Exam
JEE Main
Year
2014
Date
11 April
Mode
Online
Subject
Chemistry
Chapter
Ionic Equilibrium

JEE Main 2014 · 11 April · Online · Chemistry · Ionic Equilibrium

Assuming that the degree of hydrolysis is small, the pH of 0.1 M...

Assuming that the degree of hydrolysis is small, the pH\mathrm{pH} of 0.1M0.1 \mathrm{M} solution of sodium acetate (Ka=1.0×10−5)\left(\mathrm{K}_{\mathrm{a}}=1.0 \times 10^{-5}\right) will be:

Options

  1. A5.05.0
  2. B6.06.0
  3. C8.08.0
  4. D9.09.0

Correct answer

D. 9.09.0

Step-by-step solution

Sodium acetate is a salt of strong base and weak acid. ∴pH=7+12pKa+12log⁡c where pka=−log⁡Ka=−log⁡10−5=5log⁡c=log⁡10−1=−1pH=7+52−12=9.0\begin{aligned} &\therefore \mathrm{pH}=7+\frac{1}{2} \mathrm{p} K_a+\frac{1}{2} \log c \quad \text{ where } \\ &\mathrm{p} k_a=-\log K_a=-\log 10^{-5}=5 \\ &\log \mathrm{c}=\log 10^{-1}=-1 \\ &\mathrm{pH}=7+\frac{5}{2}-\frac{1}{2}=9.0 \end{aligned}
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