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JEE Main 2012Offline
Exam
JEE Main
Year
2012
Mode
Offline
Subject
Chemistry
Chapter
Ionic Equilibrium

JEE Main 2012 · Offline · Chemistry · Ionic Equilibrium

The pH of a 0.1 molar solution of the acid HQ is 3 . The value of...

The pH of a 0.10.1 molar solution of the acid HQ\mathrm{HQ} is 33 . The value of the ionization constant, Ka of this acid is :

Options

  1. A3×10−13 \times 10^{-1}
  2. B1×10−31 \times 10^{-3}
  3. C1×10−51 \times 10^{-5}
  4. D1×10−71 \times 10^{-7}

Correct answer

C. 1×10−51 \times 10^{-5}

Step-by-step solution

[H+]=Ka⋅C⇒10−3=Ka⋅10−1⇒Ka=10−5\left[\mathrm{H}^{+}\right]=\sqrt{\mathrm{K}_{\mathrm{a}} \cdot \mathrm{C}} \Rightarrow 10^{-3}=\sqrt{\mathrm{K}_{\mathrm{a}} \cdot 10^{-1}} \Rightarrow \mathrm{K}_{\mathrm{a}}=10^{-5}
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