Highly selective Backlog Qs for JEE MainChemistryChemical Equilibrium
The reaction, 2 ~A ( ~g )+ B ( g ) 3 C ( g )+ D ( g ) is begun with the concentrations of A and B both at an initial value of 1.00 M . When equilibrium is reached, the concentration of D is measured and found to be 0.25 M . The value for the equilibrium constant for this reaction is given by the expression
Options
- A[(0.75)³(0.25) ] [(1.00)²(1.00) ]
- B[(0.75)³(0.25) ] [(0.50)²(0.75) ]
- C[(0.75)³(0.25) ] [(0.50)²(0.25) ]
- D[(0.75)³(0.25) ] [(0.75)²(0.25) ]
Correct answer
B. [(0.75)³(0.25) ] [(0.50)²(0.75) ]
Step-by-step solution
Thereaction- 2 A( ~g )+B( ~g ) 3 C( ~g )+D( ~g ) Initial 1 1 At equil 1-0.501-0.25 0.75 0 ~K = (0.75)³(0.25) (0.50)²(0.75)