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The product that should be formed in the reaction is: CH 3 - C ≡ C - CH 3 → i   H 2 ,    lindlar ′ s   catalyst ( ii )   Br 2 / CCl 4 Product

Options

  1. AI and IIl in equal amounts
  2. BII and IV in equal amounts
  3. CAll four in unequal amounts
  4. DI and II in unequal amount

Correct answer

A. I and IIl in equal amounts

Step-by-step solution

CH 3 - C ≡ C - C H 3 →   H 2 ,    lindlar ' s   catalyst Cis - 2 - butene Cis - 2 - butene → Br 2 / CCl 4 2 , 3 - dibromobutane ( racemic   mixture )

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