0.5 ~g of an acid is neutralised by 40 cc of 0.125 ~N NaOH . The equivalent mass of the acid is

Correct answer: B. 100 Equivalent moles of NaOH= Equivalent moles of acid N_ 1 V_ 1 = Weight Equivalent mass 40 × 10^ -3 × 0.125= 0.5 Equivalent mass Equivalent mass of acid =100

JEE Main

Exam: JEE Main
Subject: Chemistry
Chapter: Redox Reactions

JEE Main · Chemistry · Redox Reactions

0.5 ~g of an acid is neutralised by 40 cc of 0.125 ~N NaOH . The...

0.5 \mathrm{~g}

of an acid is neutralised by

40 \mathrm{cc}

0.125 \mathrm{~N} \mathrm{NaOH}

. The equivalent mass of the acid is

Options

A50
B100
C40
D80

Correct answer

B. 100

Step-by-step solution

Equivalent moles of

\mathrm{NaOH}=

Equivalent moles of acid

N_{1} V_{1}=\frac{\text { Weight }}{\text { Equivalent mass }}40 \times 10^{-3} \times 0.125=\frac{0.5}{\text { Equivalent mass }}\therefore

Equivalent mass of acid

=100

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