50 ~cm ³ of 0.2 ~N HCl is titrated against 0.1 ~N NaOH solution. The titration is discontinued after adding 50 ~cm ³ of NaOH . The remaining titration is completed by adding 0.5 ~N KOH . The volume of KOH required for completing the titrati

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50 ~cm ³ of 0.2 ~N HCl is titrated against 0.1 ~N NaOH solution. The titration is discontinued after adding 50 ~cm ³ of NaOH . The remaining titration is completed by adding 0.5 ~N KOH . The volume of KOH required for completing the titration is

Quantrex Academy · Accepted Answer

Correct answer: B. 10 ~cm ³

When 0.1 ~N NaOH is used, gathered N ₁ ~V ₁= N ₂ ~V ₂ (For HCl) (For NaOH) 0.2 ~N V ₁=50 0.1 ~N ~V ₁= 50 0.1 0.2 =25 ~cm ³ gathered When 0.5 ~N KOH is used, aligned N ₁ ~V ₁=& N ₃ ~V ₃ (For remaining HCl) &( For KOH ) 0.2 ~N 25 &=0.5 ~N V ₃ ~V ₃ &= 0.2 25 0.5 =& 10 ~cm ³ aligned

50 ~cm ³ of 0.2 ~N HCl is titrated against 0.1 ~N NaOH solution. The titration is discontinued after adding 50 ~cm ³ of NaOH . The remaining titration is completed by adding 0.5 ~N KOH . The volume of KOH required for completing the titration is

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