KMnO ₄ reacts with KI , in basic medium to form I ₂ and MnO ₂ . When 250 ~mL of 0.1 M KI solution is mixed with 250 ~mL of 0.02 M KMnO ₄ in basic medium, what is the number of moles of I ₂ formed?

Step-by-step solution

array r -factor =1 MnO ₄⁻+ I ⁻ MnO ₂+ I ₂ _ n -factor =3 ^ array Number of milli equivalents of MnO ₄⁻=0.02 3 250=15 Number of milli equivalents of I ₂=0.1 1 250=25 Thus, here MnO ₄⁻ is limiting reagent. Number of milli equivalents of I ₂ formed = Number of milli equivalent of MnO ₄⁻=15 or number of equivalent of I ₂ formed = 15 1000 =0.015 aligned Number of moles of I ₂ formed & = 0.015 2 & =0.0075 aligned