Highly selective Backlog Qs for JEE MainMathematicsStraight Lines

The equation of a given straight line is x-x₁ = y-y₁ = . If the equation of the line perpendicular to the given line and passing through ( , ) is x a + y b =1 , then b a is equal to

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B-

Correct answer

Step-by-step solution

Given equation of line is x-x₁ = y-y₁ = Slope of Eq. (i) is m= So, slope of a line perpendicular to Eq. (i) is (- ) . According to the question, equation of required line is x a + y b =1 Slope of line (ii) is ( -b a ) So, -b a =- b a =

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