Highly selective Backlog Qs for JEE MainMathematicsStraight Lines
The equation of the line passing through the point of intersection of the lines x-3 y+2=0 and 2 x+5 y-7=0 and perpendicular to the line 3 x+2 y+5=0 is :
Options
- A2 x-3 y+1=0
- B6 x-9 y+11=0
- C2 x-3 y+5=0
- D3 x-2 y+1=0
Correct answer
A. 2 x-3 y+1=0
Step-by-step solution
The equation of lines are x-3 y+2=0 ...(i) and 2 x+5 y-7=0 ...(ii) On solving Eqs. (i) and (ii), we get x=1, y=1 The co-ordinates of a point of intersection of given lines are (1,1) . The equation of line perpendicular to 3 x+2 y+5=0 is 2 x-3 y+ =0 . Which passes through (1,1) . 2-3+ =0 =1 Required equation of line is 2 x-3 y+1=0