Highly selective Backlog Qs for JEE MainPhysicsOscillations
The variation of kinetic energy (KE) of a particle executing simple harmonic motion with the displacement (x) starting from mean position to extreme position (A) is given by
Correct answer
3
Step-by-step solution
aligned & T E=K E+P . E & K E=T E-K E & = 1 2 k^2- 1 2 k^2 & K E= 1 2 m ^2 (A^2-x^2 ) [ k=m ^2 ] aligned KE is maximum at x =0 & KE is zero when x = A K . E vs x graph is parabola.