Highly selective Backlog Qs for JEE MainPhysicsOscillations
A particle is performing S.H.M between x = - A and x = + A . The position of particle where K.E. equals to P.E.
Options
- Ax = 0
- Bx = + A
- Cx = + A 2
- Dx = 3 2 A
Correct answer
C. x = + A 2
Step-by-step solution
K E = 1 2 k x 2 P E = 1 2 K A 2 - x 2 1 2 K x 2 = 1 2 K A 2 - x 2 x 2 = A 2 2 x = A 2