Most Important Selected Qs for JEE AdvancedChemistrySolutions
Consider the following values of K _ H for given gases at 293 ~K . ( K _ H = . Henry's constant, K _ H is given in bar) He =144.97, H ₂=69.16, ~N ₂=76.48, O ₂=34.86 Select the correct option(s).
Options
- ACorrect order of solubility is He N ₂ H ₂ O ₂ in water if each gas has partial pressure 1 atm
- BCorrect order of solubility is O ₂ H ₂ N ₂ He in water if each gas has partial pressure 1 atm
- CCorrect order of mole fraction is N ₂ O ₂ when air is dissolved in water, if air consist 80 % ~N ₂ and 20 % O
- DIf partial pressure of O ₂ and N ₂ are 1 atm , then mole fraction of N ₂ is 0.46 (approx) times that of O ₂
Correct answer
D. If partial pressure of O ₂ and N ₂ are 1 atm , then mole fraction of N ₂ is 0.46 (approx) times that of O ₂
Step-by-step solution
aligned X_ N₂ & = P K_H = 0.8 101325 76480 10^5 & =1.06 10⁻⁵ aligned aligned & X _ O ₂ = 0.2 101325 34860 10^5 &=5.8 10⁻⁶ & X _ N ₂ X _ O ₂ = P _ N ₂ ~K _ H _ O ₂ ~K _ H _ N ₂ P _ O ₂ & X _ N ₂ X _ O ₂ = 34.86 76.48 aligned