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Most Important Selected Qs for JEE AdvancedMathematicsDeterminants

If the system of equations, a^2 x-b y=a^2-b & b x-b^2 y=2+4 b possess an infinite number of solutions then the possible values of 'a' and 'b' are

Options

  1. Aa =1, ~b =-1
  2. Ba=1, b=-2
  3. Ca=-1, b=-1
  4. Da=-1, b=-2

Correct answer

D. a=-1, b=-2

Step-by-step solution

a^2 b = b b^2 = a^2-b 2+4 b a^2 b^2=b^2 b^2 (a^2-1 ) a=1 or -1 & b=0 , if a =1 then 2+4 ~b = b - b ^2 ~b ^2+3 ~b +2=0 ~b =-2 or -1 ; if a=-1 then b=-2 or -1

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