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Most Important Selected Qs for JEE AdvancedMathematicsHyperbola

| (x-4)^2+(y-2)^2 - (x+4)^2+(y+2)^2 |=4 is equation of -

Options

  1. Aan ellipse with centre (0,0)
  2. Ba hyperbola with centre (0,0)
  3. Ca conic section whose eccentricity is 5
  4. Da conic whose auxillary circle is x^2+y^2=4

Correct answer

D. a conic whose auxillary circle is x^2+y^2=4

Step-by-step solution

It is locus of P ( x , y ) moving such that ( PS - PS ^ )=4 SS ^ , where S (4,2) and S^ (-4,-2) . So the locus is hyperbola with S , S ^ as foci. Centre is mid point of SS ^ . 2 a =4,2 ae =4 5 e= 5 auxiliary circle is concentric circle with radius 'a' so x^2+y^2=4 .

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