If P(t)= _ r - _ r=2 ^n t^ 2 r-3 (1-t) ( t^ 2 r-1 +1 ) ( t^ 2 r-3 +1 ) , then P ( 1 2 ) lies in the interval:

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Quantrex Academy · Accepted Answer

Correct answer: B. (0, 4 )

aligned P(t) & = _ n _ r=2 ^n ( t^ 2 r-3 - t^ 2 r-1 ( t^ 2 r-1 +1 ) ( t^ 2 r-3 +1 ) )= _ n _ r=2 ^n ( t^ 2 r-3 +1 )- ( t^ 2 r-1 +1 ) ( t^ 2 r-1 +1 ) ( t^ 2 r-3 +1 ) & = _ n _ r=2 ^n ( 1 t^ 2 r-1 +1 - 1 t^ 2 r-3 +1 )= _ n ( 1 t^ 2 n-1 +1 - 1 t +1 ) aligned For t (0,1) aligned & P(t)=1- 1 t +1 = t t +1 & P ( 1 2 )= 2 -1 0.414 & aligned

If P(t)= _ r - _ r=2 ^n t^ 2 r-3 (1-t) ( t^ 2 r-1 +1 ) ( t^ 2 r-3 +1 ) , then P ( 1 2 ) lies in the interval:

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