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For the equation 3 2 x= 2 x+2 x 2 (1+ x) which of the following holds good?

Options

  1. AThe number of solutions of the equation in [0,2 ] is 4
  2. BThe number of solutions of the equation in [0,2 ] is 3
  3. CIf is the smallest positive root of the equation then 2 +2 2 - 3 =2+ 3
  4. DIf is the smallest positive root of the equation then 2 +2 4 + 3 =2- 3

Correct answer

D. If is the smallest positive root of the equation then 2 +2 4 + 3 =2- 3

Step-by-step solution

aligned & 3 2 2 x- 1 2 2 x= x 2 (2 ^2 x 2 ) & (2 x- 6 )= x & 2 x- 6 =n +(-1)^n x aligned When, x is even, x=2 k + 6 Solution = 6 When, x is odd, x= (2 k-1) 3 + 18 Solution = 7 18 , 19 18 , 31 18 Now, verify.

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