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JEE Advanced
Exam
JEE Advanced
Subject
Mathematics
Chapter
Trigonometry

JEE Advanced · Mathematics · Trigonometry

If ∑_ m=1 ^6 (α+(m-1) (π)/(4)) (α+(m π)/(4))=4 2 , where α ∈(0, π)...

If ∑m=16csc⁡(α+(m−1)π4)csc⁡(α+mπ4)=42\sum_{m=1}^6 \csc \left(\alpha+(m-1) \frac{\pi}{4}\right) \csc \left(\alpha+\frac{m \pi}{4}\right)=4 \sqrt{2}, where α∈(0,π)\alpha \in(0, \pi) then α\alpha can be:

Options

  1. Aπ12\frac{\pi}{12}
  2. Bπ6\frac{\pi}{6}
  3. C5π12\frac{5 \pi}{12}
  4. Dπ3\frac{\pi}{3}

Correct answer

C. 5π12\frac{5 \pi}{12}

Step-by-step solution

∑m=16csc⁡(α+(m−1)π4)csc⁡(α+mπ4)=42\sum_{m=1}^6 \csc \left(\alpha+(m-1) \frac{\pi}{4}\right) \csc \left(\alpha+\frac{m \pi}{4}\right)=4 \sqrt{2} On solving, we get sin⁡2α=12\sin 2 \alpha=\frac{1}{2} Hence, 2α=π6\quad 2 \alpha=\frac{\pi}{6} or 5π6⇒α=π12\frac{5 \pi}{6} \quad \Rightarrow \quad \alpha=\frac{\pi}{12} or 5π12\frac{5 \pi}{12}
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