A reaction has rate constant k=2.4 10⁻⁴ ~s ⁻¹ . Then, find the ratio of t_ 99.9 to t₅₀ .

Step-by-step solution

Unit of k is s ⁻¹ . It is first order reaction aligned t_ 99.9 % & = 2.303 k 100 0.1 & = 2.303 k 1000= 2.303 k 10^3 & = 2.303 k 3 10= 2.303 k 3 [ 10=1] t_ 50 % & = 0.693 k aligned Ratio of t_ 99.9 % and t_ 50 % is t_ 99.9 % t_ 50 % = 3 2.303 / k 0.693 / k =10 .