An equal volume of a reducing agent is treated separately with 1 M KMnO ₄ in acid, neutral and alkaline medium. The volumes of KMnO ₄ required are 20 ml in acid, 33.4 ml in neutral and 100 ml in alkaline medium. Find out the oxidation state of manganese in each reaction product. Find out the volume of 1 M K ₂ Cr ₂ O ₇ consumed, if the same volume of the reducing agent is treated in acid medium. (mark the answer in ml

Step-by-step solution

Let N ₁, ~N ₂ and N ₃ be the normalitics of 1 M KMnO 4 solution in acidic, neutral and alkaline medium respectively. aligned & 20 ml ~N ₁ 33.4 ml ~N ₂ 100 ml ~N ₃ aligned In acidic medium 1 M KMnO ₄=5 ~N KMnO ₄ Thus N ₂= 20 33.4 ~N ₁= 20 33.4 5 ~N =3 ~N N₃= 20 100 N₁= 20 5 ~N 100 =1 ~N The volume required for titration of the same volume of reducing agent with acidified K ₂ Cr ₂ O , solution aligned & 20 ml 5 ~N KMnO ₄= V ₆ NK ₂ Cr ₂ O ₇ & ~V = 20 5 6 =16.66 ml aligned