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A liquid (X) of molecular mass 77 on steam distillation at 760 mmHg atmospheric pressure gave a distillate containing 25 % by mass of (X) . What is the vapour pressure of (X) in mmHg at the temperature of distillation to the nearest integer?

Correct answer

55

Step-by-step solution

For immiscible liquids (X) and water, (at the boiling temperature) if P is the vapour pressure of liquid (X) then P_x P_w = n_x n_w P 760-P = (W_x ) (M_w ) M_x W_w = 25 18 77 75 On solving P=55 mmHg

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