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If a₁, a₂, a₃, ., a₁₂ are in A.P. and ₁= | array lll a₁ a₅ & a₁ & a₂ a₂ a₆ & a₂ & a₃ a₃ a₇ & a₃ & a₄ array |, ₂= | array lll a₂ a₁₀ & a₂ & a₃ a₃ a₁₁ & a₃ & a₄ a₃ a₁₂ & a₄ & a₅ array | then ₁: ₂ is equal to

Correct answer

1

Step-by-step solution

Here, ₁=d (a₁-a₂ ) (a₂-a₃ ) (a₃-a₁ )=-2 d^4 Also, ₂=-2 ~d ^4

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