Most Important Selected Qs for JEE AdvancedMathematicsStraight Lines

The extremities of a diagonal of a rectangle are (0,0) and (4,4) . The locus of the extremities of the other diagonal is x^2+y^2- ₁ x- ₂ y=0 , then find the value of ( ₁+ ₂ ) .

Correct answer

Step-by-step solution

The locus of the extremities of the other diagonal is the eirele with given diagonal as diameter. aligned & (x-0)(x-4)+(y-4)(y-0) =0 & x^2+y^2-4 x-4 y =0 & Aliter: (A E)^2 =(D E)^2 & (h-2)^2+(k-2)^2 =(2 2 )^2 & x^2+y^2-4 x-4 y =0 aligned

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