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Most Important Selected Qs for JEE AdvancedMathematicsTrigonometry

Given that x R , find the minimum value of (3 5-4 x + 13-12 x )^2 .

Correct answer

40

Step-by-step solution

aligned E & =(3 5-4 x + 13-12 x ) & =( 45-36 x + 13-12 x ) & = ( (6-3 x)^2+(3 x)^2 + (2-3 x)^2+(3 x)^2 ) & =P A+ .P B |_ minimum =A B= 40 aligned Where aligned & P=3 x, 3 x & A=(6,0) and B=(0,2) aligned Hence, minimum value of E^2=40

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