Paragraph : 10 moles of NH ₃ is heated at 15 atm from 27^ C to 347^ C assuming volume constant. The pressure at equilibrium is found to be 50 atm . The equilibrium constant for the dissociation of NH ₃2 NH ₃( ~g ) N ₂( ~g )+3 H ₂( ~g ), H =91.94 ~kJ Can be written as K _ P = P _ N ₂ ( P _ H ₂ )^3 ( P _ NH ₃ )^2 ( ~atm )^2 Answer, the following questions: Question : The volume of the container in which the gas is heat