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Paragraph: Let a, b, c, d R . Then the cubic equation of the type a x^3+b x^2+c x+d=0 has either one root real or all three roots are real. But in case of trigonometric equations of the type a ^3 x+b ^2 x+c x+d=0 can possess several solutions depending upon the domain of x . To solve an equation of the type a +b =c . The equation can be written as ( - )=c / (a^2+b^2 ) . The solution is =2 n + , where tan =b / a, =c /

Options

  1. ANo solution
  2. BOne solution
  3. CTwo solutions
  4. DThree solutions

Correct answer

C. Two solutions

Step-by-step solution

3= 4 x+ 10 x 1+ ^2 x = 4 x+5 2 x i.e 3=1-2 ^2 2 x+5 2 x i.e 2 x= 1 2 2 x= 6 , 5 6 Thus there are two solutions.

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