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JEE Advanced
Exam
JEE Advanced
Subject
Mathematics
Chapter
Trigonometry

JEE Advanced · Mathematics · Trigonometry

Paragraph: While finding the sine of a contain angle x , an absent...

Paragraph: While finding the sine of a contain angle xx, an absent minded professor failed to notice that his calculator was not in the correct angular mode. However he was lucky to get right answer. The two least positive value of xx for which the sine of xx degree is the same as the sine of xx radian found by him as mπn−π\frac{m \pi}{n-\pi} and pπq+π\frac{p \pi}{q+\pi}, where m,n,pm, n, p and qq are positive integers. Suppose mnpq\frac{m n}{p q} be denoted by quantity ' LL 'Question: The value of (m+n+p+q)(m+n+p+q) is equal to

Options

  1. A720
  2. B900
  3. C1080
  4. D1260

Correct answer

B. 900

Step-by-step solution

sin⁡x=sin⁡(πx)180⇒sin⁡x=sin⁡(π−πx180) or sin⁡(2π+πx180)x=π−πx180,x=2π+πx180x=180π180+π,x=360π180−π\begin{aligned} & \sin x=\sin \frac{(\pi x)}{180} \Rightarrow \sin x=\sin \left(\pi-\frac{\pi x}{180}\right) \text { or } \sin \left(2 \pi+\frac{\pi x}{180}\right) \\ & x=\pi-\frac{\pi x}{180}, x=2 \pi+\frac{\pi x}{180} \\ & x=\frac{180 \pi}{180+\pi}, x=\frac{360 \pi}{180-\pi} \end{aligned} On comparing, m=360,n=180,p=180,q=180⇒(m+n+p+q)=900m=360, n=180, p=180, q=180\Rightarrow(m+n+p+q)=900
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