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Paragraph: The time-period of a simple pendulum performing simple harmonic motion, having length is given T =2 ~g This formula holds good if following conditions are satisfied. (i) String is massless and extensible. (ii) Bob is a point mass. (iii) Angular displacement about mean position is very small, and (iv) Length of string is very small as compared to the radius of earth ( R _ e ) . Question: If the bob is a sol

Options

  1. A2 5 R ^2 ( ~L + R ) +( R + L )
  2. B2 5 R ^2 ~L + L
  3. CR + L
  4. DL

Correct answer

A. 2 5 R ^2 ( ~L + R ) +( R + L )

Step-by-step solution

R = radius of gyration about mass centre = 2 R 5 = distance between point of suspension and mass centre = L + R _ eq = k ^2 + = 2 5 R ^2 ( ~L + R ) +( L + R )

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