Most Important Selected Qs for JEE AdvancedChemistryChemical Equilibrium
For the following equilibria in a close container PCl ₅( ~g ) PCl ₃( ~g )+ Cl ₂( ~g ) At a constant temperature, the volume of the container is halved suddenly. Which of the following is correct for K _ p and ?
Options
- ABoth K_p and changes
- BNone of the K_p and change
- CK _ p changes but does not
- D- changes but K_p does not
Correct answer
D. - changes but K_p does not
Step-by-step solution
PCl ₅( ~g ) PCl ₃( ~g )+ Cl ₂( ~g ) K_c= x^2 ^2 x(1- ) V , also K_p=K_c(R T)^ n on reducing volume to V 2 , initial concentration of PCl ₅ doubles and its degree of dissociation is increased but K_p does not change, as it is characteristic constant for a reaction at constant temperature.