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How many ml of 0.05 M KMnO ₄ (acid) are required to oxidize 2.0 gram of FeSO ₄ in dilute solution?

Options

  1. A52.63
  2. B42.63
  3. C12.63
  4. D21.36

Correct answer

A. 52.63

Step-by-step solution

The redox changes are aligned & Mn ⁷⁺+5 e ⁻ Mn ²⁺ & Fe ²⁺ Fe ³⁺+1 e ⁻ aligned Equivalent weight of FeSO ₄= 152 1 Milli equivalent of KMnO ₄= Meq. Of FeSO ₄ aligned & 0.05 5 V = 2 152 / 1 1000 & V =52.63 ml aligned

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