Most Important Selected Qs for JEE AdvancedChemistrySolutions
The vapour pressure of a solution of 5 g of non-electrolyte in 100 g of water at particular temperature 2985 Nm ⁻² . The vapour pressure of pure water at that temperature is 3000 Nm ⁻² . The molecular weight the solute is
Options
- A180
- B90
- C270
- D200
Correct answer
A. 180
Step-by-step solution
aligned & W₂=5 ~g , ~W ₁=100 ~g & P ₃=2985 Nm ⁻² & P ^0=3000 Nm ⁻² & M ₂=? & P ^0-P_s P^0 = W₂ M₂ M₁ W₁ & M₂= W₂ M₁ P^0-P_s P^0 W₁ = 5 18 ( 3000-2985 3000 ) 100 & M₂=180 aligned