Most Important Selected Qs for JEE AdvancedPhysicsOscillations
Column I shows spring block system with a constant force permanently acting on block match entries of column I with column II.
Options
- A(A) - (P, Q, R), (B) - (P, Q, S), (C) - (R, S, T), (D) - (P, S, T)
- B(A) - (P, Q, R, S), (B) - (Q, R, T), (C) - (R, S), (D) - (P, T)
- C(A) - (P, Q, R, S, T), (B) - (P, Q, R, S, T), (C) - (P, Q, R, S), (D) - (P, Q, R, S)
- D(A) - (Q, R, S, T), (B) - (P, Q, S, T), (C) - (P, Q, R), (D) - (R, S, T)
Correct answer
C. (A) - (P, Q, R, S, T), (B) - (P, Q, R, S, T), (C) - (P, Q, R, S), (D) - (P, Q, R, S)
Step-by-step solution
(A) For equilibrium : 2 mg = kx ; x = 2 mg k ; A = 2 mg k v _ = A = 2 mg k k ~m =2 ~g ~m k ; a _ = ^2 ~A = k ~m 2 mg k =2 ~g (B) Same as (A) (C) Initially : mg = kx ₀ ; 3 mg = kx ; A = 2 mg k Spring will not acquire natural length. x = mg k