The rate constants for a reaction at 400 K and 500 K are 2 . 60 × 10 - 5 s - 1 and 2 . 60 × 10 - 3 s - 1 ,respectively. The activation energy of the reaction in kJmol - 1 is ______

Step-by-step solution

The relation between rate constant at two different temperatures and activation energies is given by : log K 2 K 1 = E a 2 . 303 R 1 T 1 - 1 T 2 So, log 2 . 60 × 10 - 3 2 . 60 × 10 - 5 = E a 2 . 303 × 8 . 314 1 400 - 1 500 E a =   log 10 2 × 2 . 303 × 8 . 314 400 × 500 100 E a = 2 × 2 . 303 × 8 . 314 × 200000 100 E a = 76 . 6   KJ / mol