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Let S(x)= d x e^x+8 e^ -x +4 e^ -3 x , R(x)= d x e^ 3 x +8 e^x+4 e^ -x and M(x)=S(x)-2 R(x) . If M(x)= 1 2 ⁻¹(f(x))+c where c is an arbitrary constant then f ( _e 2 ) is equal to

Options

  1. A1 2
  2. B3 2
  3. C5 2
  4. D7 2

Correct answer

B. 3 2

Step-by-step solution

aligned & M(x)= e^x (e^ 2 x -2 ) e^ 4 x +8 e^ 2 x +4 d x & Put e^x=t aligned

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