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Indefinite Integration — JEE Main & Advanced Mathematics PYQs

297 previous year questions from Indefinite Integration with answers and solutions. Numbered list, year tags, and one-tap solutions — built for serious JEE / NEET practice.

297 questionsMathematicsSolutions on every page
1

Let f(x) = ( 16x + 24 x^2 + 2x - 15 ) dx . If f(4) = 14 _e(3) and f(7) = _e(2^ 3^ ) , , N , then + is equal to:

JEE Main 2026 Solution View → 2

Let f(x)= d x x^ ( 2 3 ) +2 x^ ( 1 2 ) be such that f(0)=-26+24 _ e (2) . If f(1)= a + b _ e (3) , where a , b Z , then a + b is equal to :

JEE Main 2026 Solution View → 3

Let f(t)= ( 1- ( _ e t ) 1- ( _ e t ) ) d t, t>1 . If f (e^ / 2 )=-e^ / 2 and f (e^ / 4 )= e^ / 4 , then equals

JEE Main 2026 Solution View → 4

Let I (x)= 3 d x (4 x+6) ( 4 x²+8 x+3 ) and I (0)= 3 4 +20 . If I ( 1 2 )= a 2 b + c , where a, b, c N , gcd (a, b)=1 , then a+b+c is equal to

JEE Main 2026 Solution View → 5

Let f(x)= (2-x² ) e ^ x ( 1+x )(1-x)^ 3 / 2 ~d x . If f(0)=0 , then f ( 1 2 ) is equal to:

JEE Main 2026 Solution View → 6

If ( x)^ -11 2 ( x)^ -5 2 d x=- p₁ q₁ ( x)^ 9 2 - p₂ q₂ ( x)^ 5 2 - p₃ q₃ ( x)^ 1 2 + p₄ q₄ ( x)^ -3 2 + C , where p_ i and q_ i are positive integers with gcd (p_ i , q_ i )=1 for

JEE Main 2026 Solution View → 7

If aligned ( 1 x + 1 x^3 ) & ( [23] 3 x⁻²⁴+x⁻²⁶ ) d x & =- 3( +1) (3 x^ +x^ )^ +1 +C, x 0, aligned ( , , Z) , where C is the constant of integration, then + + is equal to ________

JEE Main 2025 Solution View → 8

If ( 1+x^2 +x )¹⁰ ( 1+x^2 -x )^9 d x= 1 m ( ( 1+x^2 +x )^n (n 1+x^2 -x ) )+C where C is the constant of integration and m, n N , then m + n is equal to

JEE Main 2025 Solution View → 9

Let f(x)= x^3 3-x^2 d x . If 5 f( 2 )=-4 , then f(1) is equal to

JEE Main 2025 Solution View → 10

If f(x)= 1 x^ 1 / 4 (1+x^ 1 / 4 ) d x, f(0)=-6 , then f(1) is equal to :

JEE Main 2025 Solution View → 11

If 2 x^2+5 x+9 x^2+x+1 ~d x=x x^2+x+1 + x^2+x+1 + _e |x+ 1 2 + x^2+x+1 |+ C , where C is the constant of integration, then +2 is equal to _______.

JEE Main 2025 Solution View → 12

Let x^3 x ~d x=g(x)+C , where C is the constant of integration. If 8 (g ( 2 )+g^ ( 2 ) )= ^3+ ^2+ , , , Z , then + - equals :

JEE Main 2025 Solution View → 13

Let I (x)= d x (x-11)^ 11 13 (x+15)^ 15 13 . If I (37)- I (24)= 1 4 ( 1 ~b ^ 1 13 - 1 c ^ 1 13 ), b , c N , then 3( ~b + c ) is equal to

JEE Main 2025 Solution View → 14

If e ^x ( x ⁻¹ x 1-x^2 + ⁻¹ x (1-x^2 )^ 3 / 2 + x 1-x^2 ) d x= g (x)+ C , where C is the constant of integration, then g ( 1 2 ) equals :

JEE Main 2025 Solution View → 15

Let 2- x 3+ x ~d x= 1 2 ( x+ _ e | x+ x| )+C , where C is the constant of integration. Then + is equal to :

JEE Main 2024 Solution View → 16

If 1 [5] (x-1)^4(x+3)^6 ~d x= A ( x-1 x+3 )^B+ C , where C is the constant of integration, then the value of + +20 AB is__________

JEE Main 2024 Solution View → 17

Let I(x)= 6 ^2 x(1- x)^2 d x . If I(0)=3 , then I ( 12 ) is equal to

JEE Main 2024 Solution View → 18

If 1 a ^2 ^2 x+ b ^2 ^2 x ~d x= 1 12 ⁻¹(3 x)+ constant, then the maximum value of a x+ b x , is :

JEE Main 2024 Solution View → 19

If cosec ^5 x d x= x cosec x ( cossc ^2 x+ 3 2 )+ _ | x 2 |+C where , R and C is the constant of integration, then the value of 8( + ) equals _______

JEE Main 2024 Solution View → 20

If ∫ sin 3 2 x + cos 3 2 x sin 3 x cos 3 x sin ( x - θ ) d x = A cos θ tan x - sin θ + B cos θ - sin θ cot x + C , where C is the integration constant, then A B is equal to

JEE Main 2024 Solution View → 21

The integral ∫ x 8 - x 2 dx x 12 + 3 x 6 + 1 tan - 1 x 3 + 1 x 3 is equal to :

JEE Main 2024 Solution View → 22

Let f x = ∫ d x 3 + 4 x 2 4 - 3 x 2 , x < 2 3 . If f 0 = 0 and f 1 = 1 α β tan - 1 α β , α , β > 0 , then α 2 + β 2 is equal t

JEE Main 2023 Solution View → 23

∫ 0 ∞ 6 e 3 x + 6 e 2 x + 11 e x + 6 d x =

JEE Main 2023 Solution View → 24

Let I x = ∫ x + 7 x d x and I 9 = 12 + 7 log e 7 . If I 1 = α + 7 log e 1 + 2 2 , then α 4 is equal to _____.

JEE Main 2023 Solution View → 25

For α , β , γ , δ ∈ ℕ , if ∫ x e 2 x + e x 2 x log e x d x = 1 α x e β x - 1 γ e x δ x + C , where e = ∑ n = 0 &#873

JEE Main 2023 Solution View → 26

If I x = ∫ e sin 2 x cos x sin 2 x - sin x d x and I 0 = 1 , then I π 3 is equal to

JEE Main 2023 Solution View → 27

The integral ∫ x 2 x + 2 x x log 2 x d x is equal to

JEE Main 2023 Solution View → 28

Let I x = ∫ x + 1 x 1 + x e x 2 d x , x > 0 . If lim x → ∞ I x = 0 then I 1 is equal to

JEE Main 2023 Solution View → 29

Let I x = ∫ x 2 x sec 2 + tan x ( x tan x + 1 ) 2 d x If I 0 = 0 , then I π 4 is equal to

JEE Main 2023 Solution View → 30

If ∫ sec 2 x - 1 d x = α log e cos 2 x + β + cos 2 x 1 + cos 1 β x + constant, then β - α is equal to ______.

JEE Main 2023 Solution View → 31

Let f x = ∫ 2 x x 2 + 1 x 2 + 3 d x . If f 3 = 1 2 log e 5 - log e 6 , then f 4 is equal to

JEE Main 2023 Solution View → 32

For I x = ∫ sec 2 x - 2022 sin 2022 x d x , if I π 4 = 2 1011 , then

JEE Main 2022 Solution View → 33

The integral ∫ 1 - 1 3 cos x - sin x 1 + 2 3 sin 2 x d x is equal to

JEE Main 2022 Solution View → 34

∫ x 2 + 1 e x x + 1 2 d x = f x e x + C , where C is a constant, then d 3 f d x 3 at x = 1 is equal to

JEE Main 2022 Solution View → 35

If ∫ 1 x 1 - x 1 + x d x = g x + c , g 1 = 0 , then g 1 2 is equal to

JEE Main 2022 Solution View → 36

Let g : 0 , ∞ → R be a differentiable function such that ∫ x cos x - sin x e x + 1 + g x e x + 1 - x e x e x + 1 2 d x = x g x e x + 1 + C , for all x > 0 , w

JEE Main 2022 Solution View → 37

If ∫ sin x sin 3 x + cos 3 x d x = α log e | 1 + tan x | + β log e 1 - tan x + tan 2 x + γ tan - 1 2 tan x - 1 3 + C , when C is constant of integration, then

JEE Main 2021 Solution View → 38

The integral ∫ 1 ( x - 1 ) 3 ( x + 2 ) 5 4 d x is equal to : (where C is a constant of integration)

JEE Main 2021 Solution View → 39

∫ 2 e x + 3 e - x 4 e x + 7 e - x d x = 1 14 u x + v log e 4 e x + 7 e - x + C , where C is a constant of integration, then u + v is equal to

JEE Main 2021 Solution View → 40

If ∫ d x x 2 + x + 1 2 = a tan - 1 2 x + 1 3 + b 2 x + 1 x 2 + x + 1 + C , x > 0 where C is the constant of integration, then the value of 9 ( 3 a + b ) is equal to _____

JEE Main 2021 Solution View → 41

The integral ∫ ( 2 x - 1 ) cos ( 2 x - 1 ) 2 + 5 4 x 2 - 4 x + 6 d x is equal to (where c is a constant of integration)

JEE Main 2021 Solution View → 42

If f x = ∫ 5 x 8 + 7 x 6 x 2 + 1 + 2 x 7 2 d x ,   x ≥ 0 ,   f 0 = 0 and f 1 = 1 K , then the value of K is

JEE Main 2021 Solution View → 43

For real numbers α , β , γ and δ , if ∫ x 2 - 1 + tan - 1 x 2 + 1 x x 4 + 3 x 2 + 1 tan - 1 x 2 + 1 x d x = α log e tan - 1 x 2 + 1 x + β tan -

JEE Main 2021 Solution View → 44

The integral ∫ e 3 log e 2 x + 5 e 2 log e 2 x e 4 log e x + 5 e 3 log e x - 7 e 2 log e x d x , x > 0 , is equal to (where c is a constant of integration)

JEE Main 2021 Solution View → 45

The value of the integral ∫ sin θ · sin 2 θ sin 6 θ + sin 4 θ + sin 2 θ 2 sin 4 θ + 3 sin 2 θ + 6 1 - cos 2 θ d θ is (where

JEE Main 2021 Solution View → 46

If ∫ cos x - sin x 8 - sin 2 x d x = a sin - 1 sin x + cos x b + c , where c is a constant of integration, then the ordered pair a , b is equal to:

JEE Main 2021 Solution View → 47

If I 1 = ∫ 0 1 1 - x 50 100 d x and I 2 = ∫ 0 1 1 - x 50 101 d x such that I 2 = α I 1 then α equals to :

JEE Main 2020 Solution View → 48

If ∫ cos θ 5 + 7 sin θ - 2 cos 2 θ d θ = Alog e | B ( θ ) | + C , where C is a constant of integration, then B ( θ ) A can be:

JEE Main 2020 Solution View → 49

If ∫ e 2 x + 2 e x - e - x - 1 e e x + e - x d x = g ( x ) e e x + e - x + c , where c is a constant of integration, then g ( 0 ) is

JEE Main 2020 Solution View → 50

The integral ∫ x x sin x + cos x 2 d x is equal to, (where C is a constant of integration):

JEE Main 2020 Solution View → 51

Let f x = ∫ x 1 + x 2 d x x ≥ 0 . Then f 3 - f 1 is equal to :

JEE Main 2020 Solution View → 52

If ∫ sin - 1 x 1 + x d x = A x tan - 1 x + B x + C , where C is a constant of integration, then the ordered pair A x , B x can be :

JEE Main 2020 Solution View → 53

If ∫ d θ cos 2 θ tan 2 θ + sec 2 θ = λ tan θ + 2 log e f θ + C where C is a constant of integration, then the ordered pair λ , f &#952

JEE Main 2020 Solution View → 54

The integral ∫ d x ( x + 4 ) 8 7 ( x - 3 ) 6 7 is equal to: (where C is a constant of integration)

JEE Main 2020 Solution View → 55

If ∫ cos x d x sin 3 x 1 + sin 6 x 2 3 = f x 1 + sin 6 x 1 λ + c , where c is a constant of integration, then λ f π 3 is equal to

JEE Main 2020 Solution View → 56

∫ ln ⁡ x + 1 - ln ⁡ x x x + 1 d x is equal to (where C is an arbitarary constant)

NTA Abhyas JEE Main 2020 Solution View → 57

The integral ∫ x cos - 1 1 - x 2 1 + x 2 dx ; x > 0 is equal to

NTA Abhyas JEE Main 2020 Solution View → 58

∫ sin 4 ⁡ x cos 8 ⁡ x d x is equal to (where C is an arbitrary constant)

NTA Abhyas JEE Main 2020 Solution View → 59

If m is any natural number, then the value of the integral ∫ x 3 m + x 2 m + x m 2 x 2 m + 3 x m + 6 1 / m dx is (where, C is an arbitrary constant)

NTA Abhyas JEE Main 2020 Solution View → 60

∫ sin 8 x − cos 8 x 1 − 2 sin 2 x cos 2 x dx is equal to (where C is an arbitrary constant)

NTA Abhyas JEE Main 2020 Solution View → 61

If ∫ d x x + x 3 = a x + b x 3 + c x 6 + d ln ( x 6 + 1 ) + e , e being an arbitrary constant, then the value of 20 a + b + c + d is

NTA Abhyas JEE Main 2020 Solution View → 62

If I = ∫ tan ⁡ x + cot ⁡ x d x , then I equals to (where, C is an arbitrary constant)

NTA Abhyas JEE Main 2020 Solution View → 63

The graph of the antiderivative of f x = x e x 2 passes through 0 , 3 , then the value of g 2 - f 0 is

NTA Abhyas JEE Main 2020 Solution View → 64

If the integral ∫ 5  tan  x tan  x - 2 dx = x + a  log sin  x - 2  cos  x + k , then the value of a is

NTA Abhyas JEE Main 2020 Solution View → 65

Let f x = 9 x 25 + c , c > 0 . If the curve y = f - 1 x passes through 1 4 , - 5 4 and g x is the antiderivative of f - 1 x such that g 0 = 5 2 , then the value of g 1 is, (whe

NTA Abhyas JEE Main 2020 Solution View → 66

∫ ln x - 1 x + 1 x 2 - 1 dx is equal to

NTA Abhyas JEE Main 2020 Solution View → 67

The value of ∫ d x x ( x n + 1 ) is equal to

NTA Abhyas JEE Main 2020 Solution View → 68

The value of ∫ sin ⁡ 101 x . sin 99 ⁡ x d x is sin ⁡ 100 x   sin 100 ⁡ x k + 5 , then k 19 is

NTA Abhyas JEE Main 2020 Solution View → 69

If ∫ dx x - 1 3 / 4 x + 2 5 / 4 = k x - 1 x + 2 1 / 4 + c , then the number of divisors of 30 k is

NTA Abhyas JEE Main 2020 Solution View → 70

If ∫ x p q - p - 1 x p + 1 q d x = 2 ( 1+ x - p ) 1 - q λ p ( q - 1 ) + c    p , q ∈ N - 1 , then the value of λ is (here, c is an arbitrary constan

NTA Abhyas JEE Main 2020 Solution View → 71

The value of the integral ∫ e 3 s i n - 1 x 1 1 - x 2 + e 3 c o s - 1 x d x is equal to (where, c is an arbitrary constant)

NTA Abhyas JEE Main 2020 Solution View → 72

The value of the integral ∫ sin ⁡ x x 6 x c o s x - sin ⁡ x x 2 d x is (where, c is an arbitrary constant)

NTA Abhyas JEE Main 2020 Solution View → 73

If the integral Ι = ∫ x s i n x c o s x ⋅ ln ⁡ x + s i n x x dx = f x g x + c ∀ x > 0 , then the range of y = g x is (where, c is an arbitrary constant)

NTA Abhyas JEE Main 2020 Solution View → 74

If the value of integral ∫ d x x + x 2 - 1 2 = a x 3 - x + b x 2 - 1 1 b + C , (where, C is the constant of integration), then a × b is equal to

NTA Abhyas JEE Main 2020 Solution View → 75

The value of the integral ∫ x 2 - 4 x x + 6 x - 4 x + 1 x - 2 x + 1 d x is equal to

NTA Abhyas JEE Main 2020 Solution View → 76

If f x = sin ⁡ x ,   g x = cos ⁡ x and h x = c o s cos ⁡ x , then the integral Ι = ∫ f g x . f x . h x d x simplifies to - λ sin 2 ⁡ co

NTA Abhyas JEE Main 2020 Solution View → 77

The value of the integral ∫ s i n 2 x s e c 2 x + 2 1 - x 2 t a n x s i n - 1 x 1 - x 2 1 + t a n 2 x d x is (where, C is the constant of integration)

NTA Abhyas JEE Main 2020 Solution View → 78

If a function f : R → R is defined as f x = ∫ x 8 + 4 x 4 - 2 x 2 + 2 d x and f 0 = 1 , then which of the following is correct?

NTA Abhyas JEE Main 2020 Solution View → 79

The value of ∫ x - 4 x 2 x - 2 d x is equal to (where, C is the constant of integration)

NTA Abhyas JEE Main 2020 Solution View → 80

The value of ∫ x d x ( x + 3 ) x + 1 is (where, c is the constant of integration)

NTA Abhyas JEE Main 2020 Solution View → 81

If ∫ e sin ⁡ θ sin ⁡ θ + sec 2 ⁡ θ d θ is equal to f θ + C (where, C is the constant of integration) and f 0 = 0 , then the value o

NTA Abhyas JEE Main 2020 Solution View → 82

If f ( x ) is the antiderivative of 1 + 2 tan x ( tan x + sec x ) 1 2 and f π 6 = l o g 2 , then the value of f ( 0 ) is

NTA Abhyas JEE Main 2020 Solution View → 83

The integral Ι = ∫ s i n x 2 + 2 x 2 c o s x 2 d x = x H x + C , (where C is the constant of integration). If the range of H ( x ) is a , b , then the value of a + 2 b i

NTA Abhyas JEE Main 2020 Solution View → 84

Let ∫ e x ⋅ x 2 d x = f x e x + C (where, C is the constant of integration). The range of f x as x ∈ R is a , ∞ . The value of a 4 is

NTA Abhyas JEE Main 2020 Solution View → 85

The value of ∫ e x x 1 + e 2 x d x is equal to (where, C is the constant of integration)

NTA Abhyas JEE Main 2020 Solution View → 86

The integral I = ∫ 2 2 x + x d x = λ . 2 2 x + C (where, C is the constant of integration). Then the value of λ is equal to

NTA Abhyas JEE Main 2020 Solution View → 87

The value of ∫ cos ⁡ x sin 2 ⁡ x sin ⁡ x + cos ⁡ x d x is equal to

NTA Abhyas JEE Main 2020 Solution View → 88

If the integral ∫ x 4 + x 2 + 1 x 2 - x + 1 d x = f x + C , (where C is the constant of integration and x ∈ R ), then the minimum value of f ' x is

NTA Abhyas JEE Main 2020 Solution View → 89

If I n = ∫ ln ⁡ x n d x , then I 10 + 10 I 9 is equal to (where C is the constant of integration)

NTA Abhyas JEE Main 2020 Solution View → 90

The value of the integral ∫ x   1 3 1 - x 3 d x is equal to (where c is the constant of integration)

NTA Abhyas JEE Main 2020 Solution View → 91

The value of the integral Ι = ∫ e x sin ⁡ x + cos ⁡ x d x is equal to e x ⋅ f x + C , C being the constant of integration. Then the maximum value of y

NTA Abhyas JEE Main 2020 Solution View → 92

If Ι = ∫ t a n - 1 e x e x + e - x d x = t a n - 1 f x 2 2 + C (where C is the constant of integration), then the range of y = f x ∀ x ∈ R is

NTA Abhyas JEE Main 2020 Solution View → 93

The value of the integral ∫ c o s e c 2 x - 2019 c o s 2019 x d x is equal to (where C is the constant of integration)

NTA Abhyas JEE Main 2020 Solution View → 94

Let A n = ∫ tan n ⁡ x d x ,   ∀ n ∈ N . If A 10 + A 12 = tan m ⁡ x m + λ (where λ is an arbitrary constant), then the value of m is equ

NTA Abhyas JEE Main 2020 Solution View → 95

The value of the integral ∫ e x 2 + 1 x 2 x 2 - 1 x + 1 d x is equal to (where C is the constant of integration)

NTA Abhyas JEE Main 2020 Solution View → 96

If ∫ d x e x - 1 = 2 t a n - 1 f x + C , (where x > 0 and C is the constant of integration) then the range of f x is

NTA Abhyas JEE Main 2020 Solution View → 97

Let f n , x = ∫ n c o s n x d x , with f n , 0 = 0 . If the expression ∑ x = 1 89 f 1 , x simplifies to sin ⁡ a sin ⁡ b sin ⁡ c , then the value of b

NTA Abhyas JEE Main 2020 Solution View → 98

If ∫ c o s 4 x d x s i n 3 x s i n 5 x + c o s 5 x 3 5 = - 1 K 1 + c o t P x K P + C , then the value of K + P is equal to (where C is the constant of integration)

NTA Abhyas JEE Main 2020 Solution View → 99

If ∫ d x x 2 + x = ln ⁡ f x + C (where C is the constant of integration), then the range of y = f x , ∀ x ∈ R - - 1,0 is

NTA Abhyas JEE Main 2020 Solution View → 100

If Ι = ∫ d x x 3 x 8 + 1 3 / 4 = λ 1 + x 8 1 4 x 2 + c (where c is the constant of integration), then the value of λ is equal to

NTA Abhyas JEE Main 2020 Solution View → 101

The value of ∫ t a n - 1 sin ⁡ x + 1 cos ⁡ x 3 + 2 sin ⁡ x - c o s 2 x d x is (where c is the constant of integration)

NTA Abhyas JEE Main 2020 Solution View → 102

Let Ι = ∫ c o s 3 x 1 + s i n 2 x d x , then Ι is equal to (where c is the constant of integration)

NTA Abhyas JEE Main 2020 Solution View → 103

The value of ∫ 1 2 x - 1 x 2 - x d x is equal to (where c is the constant of integration)

NTA Abhyas JEE Main 2020 Solution View → 104

The value of ∫ 1 - cos ⁡ θ 3 10 1 + cos ⁡ θ 13 10 d θ is equal to (where, c is the constant of integration)

NTA Abhyas JEE Main 2020 Solution View → 105

The integral Ι = ∫ e x 1 + sin ⁡ x 1 + cos ⁡ x d x = e x f x + C (where, C is the constant of integration). Then, the range of y = f x (for all x in the doma

NTA Abhyas JEE Main 2020 Solution View → 106

Let ∫ d x x 2 + 1 - x = f x + C such that f 0 = 0 and C is the constant of integration, then the value of f 1 is

NTA Abhyas JEE Main 2020 Solution View → 107

If the integral Ι = ∫ e sin ⁡ x cos ⁡ x ⋅ x 2 + 2 x d x = e f x g x + C (where, C is the constant of integration), then the number of solution(s) of f x = g x is/are

NTA Abhyas JEE Main 2020 Solution View → 108

The value of ∫ s i n 3 x cos ⁡ x d x is equal to (where, c is the constant of integration)

NTA Abhyas JEE Main 2020 Solution View → 109

The value of the integral Ι = ∫ d x 1 + s i n x , ∀ x ∈ 0 , π 2 is equal to k ln ⁡ t a n π 4 + x 8 + c , then the value of k 2 is equal to (where, c is the constant of integration)

NTA Abhyas JEE Main 2020 Solution View → 110

The value of ∫ ln ⁡ c o t x sin ⁡ 2 x d x is equal to (where, C is the constant of integration)

NTA Abhyas JEE Main 2020 Solution View → 111

If the integral ∫ ln ⁡ x x 3 d x = f x 4 x 2 + C , where f e = - 3 and C is the constant of integration, then the value of f e 2 is equal to

NTA Abhyas JEE Main 2020 Solution View → 112

If the integral Ι = ∫ e x 2 x 3 d x = e x 2 f x + c , where c is the constant of integration and f 1 = 0 , then the value of f 2 is equal to

NTA Abhyas JEE Main 2020 Solution View → 113

The value of the ∫ s i n 8 x - c o s 8 x 1 - 2 s i n 2 x c o s 2 x d x is equal to (where, C is the constant of integration)

NTA Abhyas JEE Main 2020 Solution View → 114

The value of the integral Ι = ∫ 2 x 9 + x 10 x 2 + x 3 3 d x is equal to (where, C is the constant of integration)

NTA Abhyas JEE Main 2020 Solution View → 115

The value of the integral ∫ d x 1 + x x - x 2 is equal to (where, C is the constant of integration)

NTA Abhyas JEE Main 2020 Solution View → 116

If the integral Ι = ∫ d x x 10 + x = λ l n x 9 1 + x μ + C , (where, C is the constant of integration) then the value of 1 λ + μ is equal to

NTA Abhyas JEE Main 2020 Solution View → 117

Let the integral I = ∫ 2020 x + sin - 1 ⁡ 2020 x 1 - 2020 2 x d x = K 2 2020 sin - 1 ⁡ 2020 x + λ (where, λ is the constant of integration), then the va

NTA Abhyas JEE Main 2020 Solution View → 118

Let ∫ sin ⁡ 2 x ln ⁡ ( cos ⁡ x ) d x = ⁡ f ( x ) cos 2 ⁡ x + C , (where, C is the constant of integration) and f 0 = 1 2 . If f π 3 is equa

NTA Abhyas JEE Main 2020 Solution View → 119

If the integral I = ∫ e 5 ln ⁡ x x 6 + 1 - 1 d x = ln ⁡ x 6 + 1 + C , (where, C is the constant of integration) then the value of 1 λ is

NTA Abhyas JEE Main 2020 Solution View → 120

If f x is a differentiable function such that ∫ f x d x = 2 f x 2 + C , (where, C is the constant of integration) and f 1 = 1 / 4 , then f π equals

NTA Abhyas JEE Main 2020 Solution View →
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