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JEE Main 20241 FebruaryMorning Shift
Exam
JEE Main
Year
2024
Date
1 February
Shift
Morning Shift
Subject
Chemistry
Chapter
Redox Reactions

JEE Main 2024 · 1 February · Morning Shift · Chemistry · Redox Reactions

In acidic medium, K _ 2 Cr _ 2 O _ 7 shows oxidising action as...

In acidic medium, K2Cr2O7{K}_{2}{Cr}_{2}{O}_{7} shows oxidising action as represented in the half reaction

Cr2O72−+XH++Ye−→2A+ZH2O{Cr}_{2}{O}_{7}^{2 -} + {XH}^{+} + {Ye}^{-} \to 2A + {ZH}_{2}O X,Y,ZX, Y, Z and AA are respectively are:

Options

  1. A8,6,48, 6, 4 and Cr2O3{Cr}_{2}{O}_{3}
  2. B14,7,614, 7, 6 and Cr3+{Cr}^{3 +}
  3. C8,4,68, 4, 6 and Cr2O3{Cr}_{2}{O}_{3}
  4. D14,6,714, 6, 7 and Cr3+{Cr}^{3 +}

Correct answer

D. 14,6,714, 6, 7 and Cr3+{Cr}^{3 +}

Step-by-step solution

Potassium dichromate, K2Cr2O7{K}_{2}{Cr}_{2}{O}_{7}, is a common inorganic chemical reagent, most commonly used as an oxidizing agent in various laboratory and industrial applications. 

The balanced reaction is,

Cr2O72−+14H++6e−→2Cr3++7H2O{Cr}_{2}{O}_{7}^{2 -} + 14{H}^{+} + 6{e}^{-} \to 2{Cr}^{3 +} + 7{H}_{2}O

X=14X = 14

Y=6Y = 6

A=7A = 7

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