Given below are two statements : Statement I: S _ 8 solid undergoes...

A disproportionation reaction is a reaction in which the same element is simultaneously oxidized and reduced. In this type of reaction, a single substance gives two products, one is oxidized while the other is reduced.

${S}_{1}: {S}_{8} + 12{OH}^{⊝} \to 4{S}^{2 -} + 2{S}_{2}{O}_{3}^{2 -} + 6{H}_{2}O$

${S}_{2}: {ClO}_{4}^{⊝}$ cannot undergo disproportionation reaction as chlorine is present in its highest oxidation state.

Hence, statement $I$ is correct and $II$ is incorrect.