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JEE Main 202429 JanuaryMorning Shift
Exam
JEE Main
Year
2024
Date
29 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Redox Reactions

JEE Main 2024 · 29 January · Morning Shift · Chemistry · Redox Reactions

KMnO _ 4 decomposes on heating at 513K to form O _ 2 along with

KMnO4{KMnO}_{4} decomposes on heating at 513K513K to form O2{O}_{2} along with

Options

  1. AMnO2 and K2O2{MnO}_{2} \text{ and } {K}_{2}{O}_{2}
  2. BK2MnO4 and Mn{K}_{2}{MnO}_{4} \text{ and } Mn
  3. CMn and KO2Mn \text{ and } {KO}_{2}
  4. DK2MnO4 and MnO2{K}_{2}{MnO}_{4} \text{ and } {MnO}_{2}

Correct answer

D. K2MnO4 and MnO2{K}_{2}{MnO}_{4} \text{ and } {MnO}_{2}

Step-by-step solution

Potassium permanganate decomposes when heated, the oxidation state of manganese changes as the oxidation state of KMnO4{KMnO}_{4} is +7+ 7 decomposes to potassium manganate which oxidation state is +6+ 6 and manganese dioxide its oxidation state is +4+ 4.

It is a redox reaction in which MnMn which undergo both oxidation and reduction such type of reaction is known as a disproportionation reaction.

2KMnO4→513KK2MnO4+MnO2+O22{KMnO}_{4}\overset{513K}{\to}{K}_{2}{MnO}_{4} + {MnO}_{2} + {O}_{2}

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