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JEE Main 202313 AprilEvening Shift
Exam
JEE Main
Year
2023
Date
13 April
Shift
Evening Shift
Subject
Chemistry
Chapter
Redox Reactions

JEE Main 2023 · 13 April · Evening Shift · Chemistry · Redox Reactions

See the following chemical reaction: Cr _ 2 O _ 7 ^ 2 - + XH ^ + +...

See the following chemical reaction:

Cr2O72−+XH++6Fe2+→YCr3++6Fe3++ZH2O{Cr}_{2}{O}_{7}^{2 -} + {XH}^{+} + 6{Fe}^{2 +} \to {YCr}^{3 +} + 6{Fe}^{3 +} + {ZH}_{2}O

The sum of X, Y and Z is

Correct answer

23

Step-by-step solution

The given equation can be balanced using ion-electron method as shown below.

Fe2+→Fe3++e−{Fe}^{2 +} \to {Fe}^{3 +} + {e}^{-} -oxidation Half reaction

6e−+14H++Cr2O72−→2Cr3++7H2O6{e}^{-} + 14{H}^{+} + {Cr}_{2}{O}_{7}^{2 -} \to 2{Cr}^{3 +} + 7{H}_{2}O -Reduction Half reaction

The overall reaction is

6Fe2++14H++Cr2O72−→6Fe3++2Cr3++7H2O6{Fe}^{2 +} + 14{H}^{+} + {Cr}_{2}{O}_{7}^{2 -} \to 6{Fe}^{3 +} + 2{Cr}^{3 +} + 7{H}_{2}O

The values X=14,Y=2andZ=7X = 14, Y = 2andZ = 7

(X+Y+Z)=14+2+7( X + Y + Z ) = 14 + 2 + 7

=23= 23

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