2 IO _ 3 ^ - + xI ^ - + 12 H ^ + → 6 I _ 2 + 6 H _ 2 What is the...

Assign the oxidation number to all the elements in the reaction,

$2{\overset{+ 5}{I}{O}_{3}}^{-} + x\overset{- 1}{{I}^{-}} + 12\overset{+ 1}{{H}^{+}} \to 6\overset{0}{{I}_{2}} + 6{H}_{2}O$

$2{IO}_{3}^{-} + 10{e}^{-} \to {I}_{2}$

\left[2{I}^{-} \to {I}_{2} + 2{e}^{-}\right] \times 5$</p><p>$2{IO}_{3}^{-} + 10{I}^{-} + 12{H}^{+} \to 6{I}_{2} + 6{H}_{2}O$</p><p>Therefore, the value of$x = 10 in the reaction.