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JEE Main20236 Apr 2023Evening ShiftChemistryRedox ReactionsActual

The volume of 0 . 02 M aqueous HBr required to neutralize 10 . 0 mL of 0 . 01 M aqueous Ba ( OH ) 2 is (Assume complete neutralization)

Options

  1. A2 . 5   mL
  2. B5 . 0   mL
  3. C10 . 0   mL
  4. D7 . 5   mL

Correct answer

C. 10 . 0   mL

Step-by-step solution

The balanced chemical equation for the reaction between HBr and Ba ( OH ) 2 is: 2 HBr + Ba ( OH ) 2   →   BaBr 2 + 2 H 2 O From this equation, we can see that 2 moles of HBr react with 1 mole of Ba ( OH ) 2 . Equal equivalents will react. Number of equivalents = Normality × Volume So, N 1 V 1 = N 2 V 2 0 . 02 × V 1 = 0 . 02 × 10 V 1 = 10   ml

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