A 2 . 0g sample containing MnO _ 2 is treated with HCl liberating...

${MnO}_{2} + 4HCl ⟶ {MnCl}_{2} + {Cl}_{2}\left(g\right) + 2{H}_{2}O$

${Cl}_{2} + 2Kl ⟶ {I}_{2} + 2KCl$

${I}_{2} + 2{Na}_{2}{S}_{2}{O}_{3} ⟶ 2Nal + {Na}_{2}{S}_{4}{O}_{6}$

Mili eq. of ${MnO}_{2} =$ Mili eq. of ${Cl}_{2} =$ Mili eq. of ${I}_{2} =$ Mili eq. of Hypo.

$2\left(\dfrac{w}{87}\right) = \left[0 . 1 \times 60\right]$

$W = 261$ miligram

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