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JEE Main202127 Jul 2021Morning ShiftChemistryRedox ReactionsActual

The oxidation states of ' P ' in H 4 P 2 O 7 , H 4 P 2 O 5 and H 4 P 2 O 6 , respectively, are :

Options

  1. A7 ,   5 and 6
  2. B5 ,   4 and 3
  3. C5 ,   3 and 4
  4. D6 ,   4 and 5

Correct answer

C. 5 ,   3 and 4

Step-by-step solution

Oxidation state of P in H 4 P 2 O 7 ,   H 4 P 2 O 5 and H 4 P 2 O 6 is 5 ,   3   &   4 respectively H 4 P 2 O 7 2 x + 4 ( + 1 ) + 7 ( - 2 ) = 0 x = + 5 H 4 P 2 ¯ O 5 2 x + 4 ( + 1 ) + 5 ( - 2 ) = 0 x = + 3 H 4 P 2 ¯ O 6 2 x + 4 ( + 1 ) + 6 ( - 2 ) = 0 x = + 4

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