The oxidation states of ' P ' in H _ 4 P _ 2 O _ 7 , H _ 4 P _ 2 O _ 5 and H _ 4 P _ 2 O _ 6 , respectively, are :

Correct answer: C. 5, 3 and 4 Oxidation state of P in H _ 4 P _ 2 O _ 7 , H _ 4 P _ 2 O _ 5 and H _ 4 P _ 2 O _ 6 is 5, 3 and 4 respectively H _ 4 P _ 2 O _ 7 2x + 4 ( + 1 ) + 7 ( - 2 ) = 0 x = + 5 H _ 4 P _ 2 _ ¯ O _ 5 2x + 4 ( + 1 ) + 5 ( - 2 ) = 0 x = + 3 H _ 4 P _ 2 _ ¯ O _ 6 2x + 4 ( + 1 ) + 6 ( - 2 ) = 0 x = + 4

JEE Main 202127 JulyMorning Shift

Exam: JEE Main
Year: 2021
Date: 27 July
Shift: Morning Shift
Subject: Chemistry
Chapter: Redox Reactions

JEE Main 2021 · 27 July · Morning Shift · Chemistry · Redox Reactions

The oxidation states of ' P ' in H _ 4 P _ 2 O _ 7 , H _ 4 P _ 2 O...

The oxidation states of

' P '

{H}_{4}{P}_{2}{O}_{7}, {H}_{4}{P}_{2}{O}_{5}

and

{H}_{4}{P}_{2}{O}_{6},

respectively, are :

Options

A $7, 5$ and $6$
B $5, 4$ and $3$
C $5, 3$ and $4$
D $6, 4$ and $5$

Correct answer

C. $5, 3$ and $4$

Step-by-step solution

Oxidation state of $P$ in ${H}_{4}{P}_{2}{O}_{7}, {H}_{4}{P}_{2}{O}_{5}$ and ${H}_{4}{P}_{2}{O}_{6}$ is $5, 3 \text{ and } 4$ respectively

${H}_{4}{P}_{2}{O}_{7}$
$2x + 4 ( + 1 ) + 7 ( - 2 ) = 0$
$x = + 5$
${H}_{4}\mathop{{P}_{2}}_{¯}{O}_{5}$
$2x + 4 ( + 1 ) + 5 ( - 2 ) = 0$
$x = + 3$
${H}_{4}\mathop{{P}_{2}}_{¯}{O}_{6}$
$2x + 4 ( + 1 ) + 6 ( - 2 ) = 0$
$x = + 4$

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