4g equimolar mixture of NaOH and Na _ 2 CO _ 3 contains xg of NaOH and yg of Na _ 2 CO _ 3 . The value of x is g . (Nearest integer)

Correct answer: 0 Total mass = 4g Now NaOH: a mol W _ NaOH + W _ Na _ 2 CO _ 3 = 4 Na _ 2 CO _ 3 : ' a ' mol ⇒ 40a + 106a = 4 ⇒ a = (4)/(146)mol ⇒ therefore mass of NaOH is: (4)/(146) × 40g = 1 . 095 1

JEE Main 202120 JulyEvening Shift

Exam: JEE Main
Year: 2021
Date: 20 July
Shift: Evening Shift
Subject: Chemistry
Chapter: Redox Reactions

JEE Main 2021 · 20 July · Evening Shift · Chemistry · Redox Reactions

4g equimolar mixture of NaOH and Na _ 2 CO _ 3 contains xg of NaOH...

4g

equimolar mixture of

NaOH

and

{Na}_{2}{CO}_{3}

contains

xg

NaOH

and

yg

{Na}_{2}{CO}_{3} .

The value of

x

g .

(Nearest integer)

Correct answer

Step-by-step solution

Total mass $= 4g$

Now

$NaOH:$ a mol ${W}_{NaOH} + {W}_{{Na}_{2}{CO}_{3}} = 4$

${Na}_{2}{CO}_{3}:$ $' a '$ mol $⇒ 40a + 106a = 4$

$⇒ a = \dfrac{4}{146}mol$

$⇒$ therefore mass of $NaOH$ is: $\dfrac{4}{146} \times 40g$

$= 1 . 095 \approx 1$

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