JEE Main202116 Mar 2021Morning ShiftChemistryRedox ReactionsActual
2 MnO 4 - + bC 2 O 4 2 - + cH + → xMn 2 + + yCO 2 + zH 2 O If the above equation is balanced with integer coefficients, the value of c is _______ . (Round off to the Nearest Integer).
Correct answer
0
Step-by-step solution
Writing the half reaction Reduction half reaction MnO 4 - → Mn 2 + balancing oxygen MnO 4 - → Mn 2 + + 4 H 2 O balancing Hydrogen 8 H + + MnO 4 - → Mn 2 + + 4 H 2 O balancing charge 5 e - + 8 H + + MnO 4 - → Mn 2 + + 4 H 2 O Oxidation half C 2 O 4 2 - → CO 2 Balancing carbon C 2 O 4 2 - → 2 CO 2 Balancing charge C 2 O 4 2 - → 2 CO 2 + 2 e - Net equation 16 H + + 2 MnO 4 - + 5 C 2 O 4 2 - → 10 CO 2 + 2 Mn 2 + + 8 H 2 O So c = 16