AP EAMCET201823 Apr 2018Evening ShiftChemistryChemical KineticsActual
At T( ~K ) , the following data were obtained for a general reaction, A+B+C products array ccccc Expt. & array c Initial [A] array & array c Initial [B] array & array c Initial [C] array & Initial rate 1. & 0.02 M & 0.1 M & 0.03 M & 2.4 10⁻⁶ ~ms ⁻¹ 2. & 0.02 M & 0.2 M & 0.03 M & 4.8 10⁻⁶ ~ms ⁻¹ 3. & 0.02 M & 0.2 M & 0.06 M & 9.6 10⁻⁶ ~ms ⁻¹ 4. & 0.04 M & 0.2 M & 0.06 M & 9.6 10⁻⁶ ~ms ⁻¹ array The rate constant for th
Options
- A8.0 10⁻⁴ ~s ⁻¹
- B8.0 10⁻⁴ ~L ~mol ⁻¹ ~s ⁻¹
- C8.0 10^4 ~L ~mol ⁻¹ ~s ⁻¹
- D8.0 10⁻⁴ ~L ^2 ~mol ⁻² ~s ⁻¹
Correct answer
B. 8.0 10⁻⁴ ~L ~mol ⁻¹ ~s ⁻¹
Step-by-step solution
Comparing expt. (1) and expt. (2). When [B] is doubled rate of reaction doubles. Reaction is first order is B . Comparing expt. (2) and expt (3). When [C] is doubled rate of reaction doubles. Reaction is first order in C . Comparing expt. [3] and expt [4]. When [A] is doubled rate of reaction remains unchanged. Reaction is zero order in A . Rate law =K[A]^0[B]^ [C]^ Using data of expt. (1) we get aligned & 2.4 10⁻⁶=K[0.02]^0[0.1]^1[0.03]^1 & 2.4 10⁻⁶=K 1 0.1 0.03 & K= 2.4 10⁻⁶ 3 10⁻³ =0.8 10⁻³=8.0 10⁻⁴ ~L ~mol ⁻¹ ~